Bugfix: @(output) not expanding some Lisp exprs.

* parser.y (make_expr): This function is part of a hack for
converting some hard-coded syntax like @(if ...) or @(and ...)
in an @(output) block to a to a Lisp expression. Alas,
the crucial step of expanding the Lisp form was neglected.

1 files changed, 1 insertions, 1 deletions

diff --git a/parser.y b/parser.y
index 5b5f7105..af2efad9 100644
--- a/parser.y
+++ b/parser.y
@@ -1518,7 +1518,7 @@ static wchar_t char_from_name(const wchar_t *name)
 static val make_expr(parser_t *parser, val sym, val rest, val lineno)
 {
   val expr = cons(sym, rest);
-  val ret = cons(expr_s, expr);
+  val ret = cons(expr_s, expand(expr, nil));
 
   if (rest) {
     rlcp(expr, rest);